PDF chapter test TRY NOW
The brakes applied to a car produce an acceleration of 6 in the opposite direction to the motion. If
the car takes 2 \(s\) to stop after the
application of brakes, calculate the
distance it travels during this time.
Solution:
Time (\(t\)) \(=\) 2 \(s\)
Acceleration (\(a\)) \(=\) \(-\) 6 (Opposite direction to the motion)
Final Velocity (\(v\)) \(=\) \(0\) \(ms^{-1}\)
From the Equation of motion - I, We know that,
Substituting the given values of \(v\), \(a\) and \(t\) in the above equation, we get
\(Initial\ velocity\ (u)\ =\) \(ms^{-1}\)
From the Equation of motion - II, We know that,
Substituting the given values of \(u\), \(a\) and \(t\) in the above equation, we get
Distance travelled \(=\) \(m\).
Register for free to see more content