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Calculate the speed with which a satellite
moves if it is at a height of \(36,000\ km\) from
the Earth’s surface and has an orbital period
of \(24\ hr\).
[HINT: Take \(R = 6370\ km\) and convert \(hour\) into \(seconds\) before doing
calculation.]
Given:
\(h\) \(=\) \(36000\ km\)
\(t\) \(=\) \(24\ h\)
On converting \(hr\) to \(s\), we get \(s\).
Formula:
(or)
On substituting the given values, we get
Orbital velocity of a satellite \(=\) \(kms^{-1}\) [NOTE: Enter up to two decimal places for answers.]
On calculating speed, we get
Speed \(=\) \(kmh^{-1}\) [NOTE: Enter up to three decimal places for answers.]
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