Exemplar Exercise Problems XIX — task. Mathematics CBSE, Class 9.

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Without finding the cubes, factorise:

\((x – 2y)^3 + (2y – 3z)^3 + (3z – x)^3=\)

\(3(x – 2y) (2y – 3z) (3z – x)\)
\(3(2x –3y) (2y – 3z) (3z – x)\)
\(3(x-y)(y-z)(z-x)\)
\(3(2x – y) (2y – 3z) (3z – x)\)

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