Exemplar Exercise Problmes XVIII — task. Mathematics CBSE, Class 9.

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Without actually calculating the cubes, find the value of :

1. \((\frac{1}{2})^3+(\frac{1}{3})^3−(\frac{5}{6})^3=\)

\frac{i}{i}

2. \((0.2)^3 – (0.3)^3 + (0.1)^3=\)

Did you find an error?

45. Exemplar Exercise Problmes XVIII