Slope Intercept form — lesson. Mathematics State Board, Class 10.

PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

Book Free Demo

Suppose a straight line is neither vertical nor horizontal but cuts the

$y$ axis at a certain point. This point is called the

$y$ - intercept of the line.

The equation of the slope intercept form of the line is given by:

$y = mx + c$

where

$m$ is the slope of the line, and

$c$ is the

$y$ - intercept of the line.

Example:

1. Find the equation of the straight line whose slope is

$3$ , and

$y$ - intercept is

$1$ .

Solution:

Given that

$m = 3$ and

$c = 1$ .

Substituting the known values in the equation of the slope intercept form, we get:

$y = mx + c$

$y = 3x + 1$

$3x - y + 1 =0$

Therefore, the equation of the straight line is

$3x - y + 1 =0$ .

2. Determine the slope and

$y$ - intercept of the equation

$6x - 2y + 3 = 0$ .

Solution:

The given equation is

$6x - 2y + 3 = 0$ .

Let us write the given equation in the form of

$y = mx + c$ .

Thus,

$-2y = -6x - 3$

$y = \frac{-6}{-2}x - \frac{3}{(-2)}$

$y = 3x + \frac{3}{2}$

Comparing the above equation with the slope intercept form

$y = mc + c$ , we have:

$m = 3$ and

$c = \frac{3}{2}$

Therefore, the slope is

$3$ , and the

$y$ - intercept is

$\frac{3}{2}$ .

Previous theory

Exit to the topic

Next theory

Send feedback

Did you find an error?

Send it to us!

4. Slope Intercept form

Theory: