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Two triangles \(QPR\) and \(QSR\), right angled at \(P\) and \(S\) respectively are drawn on the same base \(QR\) and on the same side of \(QR\). If \(PR\) and \(SQ\) intersect at \(T\), prove that \(PT \times TR = ST \times TQ\).
Answer:
In \(\Delta PTQ\) and \(\Delta STR\):
Therefore, \(\Delta PTQ\) \(\Delta STR\).
Hence, it is proved.
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