UPSKILL MATH PLUS

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In the given figure, \triangle ABC is right-angled at C and DE \perp AB. Prove that \triangle ABC \sim \triangle ADE and hence find the lengths of AE and DE.
 
Answer:
 
(i) In \Delta ABC and \Delta ADE:
 
ACB=i
 
BAC=i
 
\Delta ABC  \Delta ADE
 
(ii) The length of AE is ii cm.
 
The length of DE is ii cm.