3. Two mark example problem I

$D$ and $E$ are respectively the points on the sides $AB$ and $AC$ of a $\Delta ABC$ such that $AB = 5.6 \ cm$, $AD = 1.4 \ cm$, $AC = 7.2 \ cm$ and $AE = 1.8 \ cm$, show that $DE || BC$.

 

Answer:

 

 

 

$\frac{\mathit{AD}}{\mathit{BD}}$ ≠= $\frac{\mathit{AE}}{\mathit{CE}}$

 

By Angle bisectorConverse of angle bisectorConverse of basic proportionalityBasic proportionality theorem, $DE || BC$.

 

[Note: Enter the simplified ratio.]