3. Two mark example problem I

\(D\) and \(E\) are respectively the points on the sides \(AB\) and \(AC\) of a \(\Delta ABC\) such that \(AB = 5.6 \ cm\), \(AD = 1.4 \ cm\), \(AC = 7.2 \ cm\) and \(AE = 1.8 \ cm\), show that \(DE || BC\).

 

Answer:

 

 

 

$\frac{\mathit{AD}}{\mathit{BD}}$ ≠= $\frac{\mathit{AE}}{\mathit{CE}}$

 

By Angle bisectorConverse of angle bisectorConverse of basic proportionalityBasic proportionality theorem, \(DE || BC\).

 

[Note: Enter the simplified ratio.]