Two mark example problem II — task. Mathematics State Board, Class 10.

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In above figure, \(DE || AC\) and \(DC || AP\). Prove that

\frac{BE}{EC} = \frac{BC}{CP}

Answer:

In \(\Delta BPA\), we have

DC ∥ i

By theorem:

\frac{BC}{i} = \frac{i}{DA}

- - - - - - (I)

In \(\Delta BCA\), we have

DE ∥ i

By theorem:

\frac{BE}{i} = \frac{i}{DA}

- - - - - - (II)

From (I) and (II), we get:

\frac{BE}{i} = \frac{i}{i}

Hence it is proved.

Did you find an error?

4. Two mark example problem II