Two mark example problem II — task. Mathematics State Board, Class 10.

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In above figure,

$DE || AC$ and

$DC || AP$ . Prove that

$\frac{BE}{EC} = \frac{BC}{CP}$ .

Answer:

$\Delta BPA$ , we have

$DC ∥ i$ .

By theorem:

$\frac{BC}{i} = \frac{i}{DA}$ - - - - - - (I)

$\Delta BCA$ , we have

$DE ∥ i$ .

By theorem:

$\frac{BE}{i} = \frac{i}{DA}$ - - - - - - (II)

From (I) and (II), we get:

$\frac{BE}{i} = \frac{i}{i}$

Hence it is proved.

Did you find an error?

4. Two mark example problem II