UPSKILL MATH PLUS

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Let \(A = \{x \in \mathbb{N}|1 < x < 4\}\), \(B = \{x \in \mathbb{W}|0 \leq x < 2\}\) and \(C = \{x \in \mathbb{N}|x < 3\}\). Then verify that \(A \times (B \cap C) = (A \times B) \cap (A \times C)\)
 
Answer:
 
To prove:
 
\(A \times (B \cap C) = (A \times B) \cap (A \times C)\)
 
Explanation:
 
\(B \cap C = \{\)\(\}\)
 
\(A \times (B \cap C) = \{\)\(\}\)
 
\(A \times B = \{\)\(\}\)
 
\(A \times C = \{\)\(\}\)
 
\((A \times B) \cap (A \times C) =\{\)\(\}\)
 
As a result, \(A \times (B \cap C) = (A \times B) \cap (A \times C)\)
 
Hence, we proved.