UPSKILL MATH PLUS
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Learn moreLet A = \{x \in \mathbb{N}|1 < x < 4\}, B = \{x \in \mathbb{W}|0 \leq x < 2\} and C = \{x \in \mathbb{N}|x < 3\}. Then verify that A \times (B \cup C) = (A \times B) \cup (A \times C)
Answer:
To prove:
A \times (B \cup C) = (A \times B) \cup (A \times C)
Explanation:
B \cup C = \{\}
A \times (B \cup C) = \{\}
A \times B = \{\}
A \times C = \{\}
(A \times B) \cup (A \times C) = \{\}
As a result, A \times (B \cup C) = (A \times B) \cup (A \times C)
Hence, we proved.