UPSKILL MATH PLUS
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Learn moreIf A = \{1,3,5\} and B = \{2,3\} then
(i) finds A \times B and B \times A.
(ii) Is A \times B = B \times A? If not, why?
(iii) Show that n(A \times B) = n(B \times A) = n(A) \times n(B)
Answer:
(i) A \times B = \{\}
B \times A = \{\}
(Note: Enter the ordered pairs in ascending order.)
(ii) Since all the ordered pairs of A \times B and B \times A are , then A \times B B \times A.
(iii) n(A) =
n(B) =
n(A \times B) =
n(B \times A) =
Therefore, n(A \times B) n(B \times A) n(A) \times n(B).