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If A = \{1,3,5\} and B = \{2,3\} then
 
(i) finds A \times B and B \times A.
 
(ii) Is A \times B = B \times A? If not, why?
 
(iii) Show that n(A \times B) = n(B \times A) = n(A) \times n(B)
 
Answer:
 
(i) A \times B = \{\}
 
B \times A = \{\}
 
(Note: Enter the ordered pairs in ascending order.)
 
(ii) Since all the ordered pairs of A \times B and B \times A are , then A \times B  B \times A.
 
(iii) n(A) =
 
n(B) =
 
n(A \times B) =
 
n(B \times A) =
 
Therefore, n(A \times B)  n(B \times A)  n(A) \times n(B).