Recall: Trigonometric ratios — lesson. Mathematics State Board, Class 10.

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Let

$ABC$ be a right angled triangle.

Let

$0^\circ < \theta < 90^\circ$ .

$\sin \theta = \frac{\text{Opposite side}}{\text{Hypotenuse}} = \frac{AB}{AC}$

$\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse}} = \frac{BC}{AC}$

$\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{AB}{BC}$

$\text{cosec}\: \theta = \frac{\text{Hypotenuse}}{\text{Opposite side}} = \frac{AC}{AB}$

$\sec \theta = \frac{\text{Hypotenuse}}{\text{Adjacent side}} = \frac{AC}{BC}$

$\cot \theta = \frac{\text{Adjacent side}}{\text{Opposite side}} = \frac{BC}{AB}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{1}{\tan \theta}$

$\text{cosec}\: \theta = \frac{1}{\sin \theta}$

$\sec \theta = \frac{1}{\cos \theta}$

Trigonometric ratio table

Did you find an error?

2. Recall: Trigonometric ratios