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Let us try to name some of the other classes of organic compounds using IUPAC rules:
1. ![7aa.PNG](https://resources.cdn.yaclass.in/645efd63-0253-4535-8885-1576df1267cc/7aaw300.png)
![7aa.PNG](https://resources.cdn.yaclass.in/645efd63-0253-4535-8885-1576df1267cc/7aaw300.png)
Step 1: According to rule \(1\), there is a three-membered carbon chain; hence, the root word is 'Prop'.
Step 2: According to rule \(2\), all the bonds between carbon atoms are single bond, and thus the primary suffix is ‘ane’.
Step 3: According to rule \(3\), the carbon chain is numbered from the end closest to the \(-OH\) group that has the lowest locant number, as shown below
![7bb.PNG](https://resources.cdn.yaclass.in/23f8414a-783d-4c70-9175-e550f64ab4ee/7bbw300.png)
Numbering of the carbon chain
Step 4: The locant number is \(1\) for the \(-OH\) group, and hence the secondary suffix is ‘\(-1-ol\)’.
Note: According to rule \(5\), when the primary and secondary suffixes are combined, the primary suffix's terminal 'e' is removed.
Hence, the name of the given compound is \(\text{Prop + ane + (-1-ol) = Propan-1-ol}\).
2. ![34.png](https://resources.cdn.yaclass.in/34afcf18-4f4c-4a85-ac47-1cefbc824cd5/34.png)
![34.png](https://resources.cdn.yaclass.in/34afcf18-4f4c-4a85-ac47-1cefbc824cd5/34.png)
Step 1: According to rule \(1\), there is a two-membered carbon chain; hence, the root word is 'Eth'.
Step 2: According to rule \(2\), all the bonds between carbon atoms are single bonds, and thus the primary suffix is ‘ane’.
Step 3: The given compound contains carboxylic acid group (\(-COOH\)), and hence the secondary suffix is 'oic acid'.
Note: According to rule \(5\), when the primary and secondary suffixes are combined, the primary suffix's terminal 'e' is removed.
Hence, the name of the given compound is \(\text{Eth + ane + oic acid = Ethanoic acid}\).
3. ![alde.PNG](https://resources.cdn.yaclass.in/7006d1a4-a1d6-4ff6-88e8-d4e5cf53b39e/aldew300.png)
![alde.PNG](https://resources.cdn.yaclass.in/7006d1a4-a1d6-4ff6-88e8-d4e5cf53b39e/aldew300.png)
Step 1: According to rule \(1\), there is a two-membered carbon chain; hence, the root word is 'Eth'.
Step 2: According to rule \(2\), all the bonds between carbon atoms are single bond, and thus the primary suffix is ‘ane’.
Step 3: The given compound contains an aldehyde group (\(-CHO\)), and hence the secondary suffix is 'al'.
Note: According to rule \(5\), when the primary and secondary suffixes are combined, the primary suffix's terminal 'e' is removed.
Hence, the name of the given compound is \(\text{Eth + ane + al = Ethanal}\).
4. ![8a.PNG](https://resources.cdn.yaclass.in/0daf6b72-e6e2-4939-99d9-0da547cb6361/8aw300.png)
![8a.PNG](https://resources.cdn.yaclass.in/0daf6b72-e6e2-4939-99d9-0da547cb6361/8aw300.png)
Step 1: According to rule \(1\), there is a four-membered carbon chain; hence, the root word is 'But'.
Step 2: According to rule \(2\), all the bonds between carbon atoms are single bonds, and thus the primary suffix is ‘ane’.
Step 3: The given compound contains ketone group (\(-C=O\)), and hence the secondary suffix is 'one'.
Step 4: The numbering of carbon chain occurs in such a way that the lowest possible number is given to the functional group in the chain.
So, its locant number is \(2\). Thus, the suffix is ‘\(2-one\)’.
![8b.PNG](https://resources.cdn.yaclass.in/af316f71-bc37-4240-bd71-429dd6d18eb2/8bw300.png)
Numbering of the carbon chain
Note: According to rule \(5\), when the primary and secondary suffixes are combined, the primary suffix's terminal 'e' is removed.
Hence, the name of the given compound is \(\text{But + ane + (-2-one) = Butan-2-one}\).
5. ![9a.PNG](https://resources.cdn.yaclass.in/04ba6e97-9563-4e44-a4ce-6565f72187d5/9aw300.png)
![9a.PNG](https://resources.cdn.yaclass.in/04ba6e97-9563-4e44-a4ce-6565f72187d5/9aw300.png)
Step 1: According to rule \(1\), there is a four-membered carbon chain; hence, the root word is 'But'.
Step 2: According to rule \(2\), all the bonds between carbon atoms are single bonds, and thus the primary suffix is ‘ane’.
Step 3: The given compound contains halogen group (\(Cl\)), and hence the prefix is 'chloro'.
Step 4: According to rule \(6\), the substituent is a halogen group compound located at the first carbon atom.
The numbering of carbon chain occurs in such a way that the lowest possible number is given to the functional group in the chain.
![9bb.PNG](https://resources.cdn.yaclass.in/75bb9fff-2af1-4231-a3d0-4aa644612617/9bbw300.png)
Numbering of the carbon chain
So, its locant number is \(1\). Thus, the prefix is ‘\(1-chloro\)’.
Hence, the name of the given compound is \(\text{1-chloro + But + ane = 1-Chloro butane}\).
The below are some of the IUPAC names of various classes of compound:
![pic4.png](https://resources.cdn.yaclass.in/a79084d9-eee1-4feb-af28-f9bbdbc3c5d1/pic4w658.png)