PUMPA - SMART LEARNING
எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்
Book Free DemoAn electric iron consumes energy at the rate of \(840\ W\) when heating is at the maximum rate and \(360\ W\) when the heating is at the minimum. The voltage is \(220\ V\). What are the current and the resistance in each case?
[Note: Enter the answer up to two decimal places by rounding off the third decimal value].
The formula for power is
\(\)
From the above formula, the value of current can be easily calculated.
The resistance of the electric iron is calculated using the formula
a. When heating is at the maximum rate,
Power, \(P\) \(=\) \(840\ W\)
Voltage, \(V\) \(=\) \(220\ V\)
Current \(=\) \(A\)
Resistance \(=\)
b. When heating is at the minimum rate,
Power, \(P\) \(=\) \(360\ W\)
Voltage, \(V\) \(=\) \(220\ V\)
Current \(=\) \(A\)
Resistance \(=\)
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