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If in figure, \(R_{1}\) \(=\) \(10\) Ω, \(R_{2}\) \(=\) \(40\) Ω, \(R_{3}\) \(=\) \(30\) Ω, \(R_{4}\) \(=\) \(20\) Ω, \(R_{5}\) \(=\) \(60\) Ω, and a \(12\ V\) battery is connected to the arrangement.
  
Calculate
a. the total resistance in the circuit, and
b. the total current flowing in the circuit.
 
series and parallel.png
Circuit diagram
 
[Note: Enter the current value up to two decimal places.]
 
Suppose we replace the parallel resistors \(R_{1}\) and \(R_{2}\) by an equivalent resistor of resistance, \(R'\). Similarly we replace the parallel resistors \(R_{3}\), \(R_{4}\) and \(R_{5}\) by an equivalent single resistor of resistance \(R"\). Then,
 
1R=iiR=iΩ
 
Similarly,
 
1R=iiR=iΩ
 
Thus, the total resistance is  Ω
 
By Ohm's law, the current formula is
 
I=ii
 
The current flowing in the circuit is  \(A\)