Intext questions XIII — task. Science CBSE, Class 10.

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எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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An electric lamp of \(100\ Ω\), a toaster of resistance \(50\ Ω\), and a water filter of resistance \(500\ Ω\) are connected in parallel to a \(220\ V\) source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?

The equivalent resistance of the resistors is

\begin{array}{l} \frac{1}{R_{P}} = \frac{1}{R_{i}} + \frac{1}{R_{i}} + \frac{1}{R_{i}} \\ = \frac{i}{i} \\ R = \frac{i}{i} Ω \end{array}

According to Ohm's law, the current is given as

i = \frac{i}{i}

On substituting the known values, we get the current drawn by the electric iron box as .

The resistance is calculated as

i = \frac{i}{i}

Therefore, the resistance of the electric iron box is .

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45. Intext questions XIII

Exercise condition: