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PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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Subjects
Science CBSE
Class 10
Light reflection and refraction
Textbook questions

12. Exercises XII

Exercise condition:

5 m.

An object of size \(7.0\ cm\) is placed at \(27\ cm\) in front of a concave mirror of focal length \(18\ cm\). At what distance from the mirror should a screen be placed so that a sharply focused image can be obtained? Find the size and nature of the image.

Mirror formula is,

\(\frac{1}{v}\ -\ \frac{1}{u}\ =\ \frac{1}{f}\)
\(\frac{1}{v}\ +\ \frac{1}{u}\ =\ \frac{1}{f}\)
\(\frac{1}{u}\ =\ \frac{1}{v}\ +\ \frac{1}{f}\)
\(\frac{1}{v}\ =\ \frac{1}{f}\ +\ \frac{1}{u}\)

Magnification is,

\(M\ =\ \frac{-u}{v}\)
\(M\ =\ \frac{v}{u}\)
\(M\ =\ \frac{-v}{u}\)
\(M\ =\ \frac{u}{v}\)

Image distance (\(v\)) \(=\) \(cm\)

Magnification (\(M\)) \(=\)

Height of the image (\(h_i\)) \(=\) \(cm\)

Nature of the image is,

virtual, erect and enlarged size
virtual, erect and diminished size
real, inverted and diminished size
real, inverted, and enlarged size

Important!

Note: Enter your answers with no decimal digits.

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