Login

Sign up

Start

PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

Book Free Demo

Subjects
Science CBSE
Class 10
Light reflection and refraction
Textbook questions

11. Exercises XI

Exercise condition:

5 m.

An object \(5\ cm\) is placed at a distance of \(20\ cm\) in front of a convex mirror of radius of curvature \(30\ cm\). Find the position, nature and size of the image.

Formula to focal length of the mirror is,

\(f\ =\ 4R\)
\(f\ =\ \frac{R}{2}\)
\(f\ =\ 2R\)
\(f\ =\ \frac{R}{4}\)

Mirror formula is,

\(\frac{1}{v}\ =\ \frac{1}{f}\ +\ \frac{1}{u}\)
\(\frac{1}{u}\ =\ \frac{1}{v}\ +\ \frac{1}{f}\)
\(\frac{1}{v}\ -\ \frac{1}{u}\ =\ \frac{1}{f}\)
\(\frac{1}{v}\ +\ \frac{1}{u}\ =\ \frac{1}{f}\)

Magnification is,

\(M\ =\ \frac{v}{u}\)
\(M\ =\ \frac{u}{v}\)
\(M\ =\ \frac{-u}{v}\)
\(M\ =\ \frac{-v}{u}\)

Focal length (\(f\)) \(=\) \(cm\)

Image distance (\(v\)) \(=\) \(cm\)

Magnification (\(M\)) \(=\)

Height of the image (\(h_i\)) \(=\) \(cm\)

Nature of the image is,

real, inverted and diminished size
virtual, erect and same size
real, inverted, and same size
virtual, erect and diminished size

Important!

Note: Enter your answers with two decimal digits.

Login or Fast registration

Previous exercise

Exit to the topic

Next exercise

Send feedback

Did you find an error?

Send it to us!

Register for free to see more content

Register now

Register for free to see more content

Register now