PDF chapter test TRY NOW
Briefly answer the following question:
Which has more number of atoms?
100g of \(N_2\) or 100 g of \(NH_3\).
100g of \(N_2\) or 100 g of \(NH_3\).
(i). 100 g of \(N_2\) = 100 / 28 moles.
Number of molecules = x \(6.022\) × \(10^2{^3}\).
Number of atoms = 2 x 100 / 28 x \(6.022\) × \(10^2{^3}\).
= x \(10^2{^3}\).
(ii). 100 g of \(NH_3\) = 100 / 17 moles.
Number of molecules = x \(6.022\) × \(10^2{^3}\).
= 100 / 17 x \(6.022\) × \(10^2{^3}\) x 4 atoms.
= x \(10^2{^3}\).
Number of molecules = x \(6.022\) × \(10^2{^3}\).
= 100 / 17 x \(6.022\) × \(10^2{^3}\) x 4 atoms.
= x \(10^2{^3}\).
Therefore,
(\(NH_3\)) would have more atoms.