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Write brief answers to the following question:
Compute the number of ions present in 5.85 g of sodium chloride.
5.85 g of NaCl = 5.85 / = 0.1 moles.
or 0.1 moles of NaCl particle.
Each NaCl particle is equivalent to one \(Na^+\) one \(Cl^-\).
⇒ 2 ions.
Total moles of ions = 0.1 x 2 = 0.2 moles.
No. of ions = 0.2 x x \(10^2{^3}\).
⇒ x \(10^2{^3}\).
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