Intext example VI — task. Science CBSE, Class 9.

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An object of mass 12 kg is at a certain height above the ground. If the potential energy of the object is 480 J, find the height at which the object is with respect to the ground. Given, \(g\ =\ 10\ m s^{–2}\).

The formula to calculate the potential energy is,

\(Height\ (h)\ =\ \frac{Potential\ energy\ (E_p)}{Mass\ (m)\ \times Acceleration\ due\ to\ gravity\ (g)}\)
\(Height\ (h)\ =\ Mass\ (m)\ \times \frac{Acceleration\ due\ to\ gravity\ (g)}{Potential\ energy\ (E_p)}\)
\(Height\ (h)\ =\ \frac{Mass\ (m) \times Potential\ energy\ (E_p)}{Acceleration\ due\ to\ gravity\ (g)}\ \)

Height of the object \(=\) \(m\)

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24. Intext example VI

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