NCERT Exemplar XVII — task. Science CBSE, Class 9.

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A girl having mass of \(35\ kg\) sits on a trolley of mass \(5\ kg\). The trolley is given an initial velocity of \(4\ m s^{-1}\) by applying a force. The trolley comes to rest after traversing a distance of \(16\ m\).

(a) How much work is done on the trolley?

(b) How much work is done by the girl?

Equation of motion,

i^{i} - i^{i} = i \times i \times i

Force is calculated by:

\(F\ =\ \frac{m}{a}\)
\(F\ =\ m \times a\)

The formula to calculate the Work done(\(W\)) is,

\(W\ =\ \frac{F}{g}\)
\(W\ =\ F \times s\)
\(W\ =\ \frac{F}{s}\)
\(W\ =\ F \times g\)

(a) Work done on the trolley \(=\) \(J\)

(b) Work done by the girl \(=\) \(J\)

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67. NCERT Exemplar XVII

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