Long answer questions III — task. Science State Board, Class 10.

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Calculate the number of moles in

i. $27$ $g$ of $Al$

ii. $1.51\times10^{23}$ molecules of $NH_4Cl$

i. Given mass of aluminium

$=27$

$g$

Molecular mass of aluminium

$=$

$\text{No. of moles}$

$=$

Where,

$=$

$mole$

ii. Given number of molecules of

$NH_4Cl$

$=1.51\times10^{23}$ molecules

Avogadro's number

$=$

$6.023\times10^{x}$

Where, x is

$\text{No. of moles}$

$=$

$mole$

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12. Long answer questions III