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Calculate the number of moles in
(i) \(27\) \(g\) of \(Al\)
(ii) \(1.51\times10^{23}\) molecules of \(NH_4Cl\)
(i) Given mass of aluminium \(=27\) \(g\)
Molecular mass of aluminium \(=\)
\(\text{No. of moles}\) \(=\)
Where,
X \(=\)
Y \(=\)
\(=\) \(mole\)
(ii) Given number of molecules of \(NH_4Cl\) \(=1.51\times10^{23}\) molecules
Avogadro's number \(=\) \(6.023\times10^{x}\)
Where, x is
\(\text{No. of moles}\) \(=\)
\(=\) \(mole\)
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