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Calculate the number of water molecules present in one drop of water that weighs 0.18 g.
  
Given data:
 
Mass of one drop of water = 0.18 g
 
Molecular mass of water =
 
Solution:
 
\text{No. of moles} =
 
Where,
 
X is
 
Y is 
 
=  mole
 
\text{No. of molecules} =\ (\text {x} )\ \cdot\ (\text {y} )
 
Where,
 
x is
 
y is
 
= 6.023\times10^{z} molecules
 
z is