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Calculate the number of water molecules present in one drop of water that weighs 0.18 g.
Given data:
Mass of one drop of water = 0.18 g
Molecular mass of water =
Solution:
\text{No. of moles} =
Where,
X is
Y is
= mole
\text{No. of molecules} =\ (\text {x} )\ \cdot\ (\text {y} )
Where,
x is
y is
= 6.023\times10^{z} molecules
z is