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Calculate the pH of \(1×10^{–4}\) molar solution of \(NaOH\).
Solution:
\(NaOH\) is a and dissociates in its solution as:
One mole of \(NaOH\) would give of \(OH^–\) ions. Therefore,
\([OH^–]=1×10^{–4}\) \(mol\) \(litre^{–1}\)
\(=–log_{10}×[10^{–4}]\)
Then,
\(=–(–4×log_{10}10)\)
Since,
\(pH=14 – pOH\)
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