Intext problems III — task. Science State Board, Class 10.

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Calculate the pH of $1×10^{–4}$ molar solution of $NaOH$ .

Solution:

$NaOH$ is a and dissociates in its solution as:

$NaOH_{(aq)}→2Na^+_{(aq)}+OH^{2–}_{(aq)}$
$NaOH_{(aq)}→Na^+_{(aq)}+OH^{–}_{(aq)}$
$NaOH_{(aq)}→Na^+_{(s)}+OH^{–}_{(aq)}$

One mole of

$NaOH$ would give of

$OH^–$ ions. Therefore,

$[OH^–]=1×10^{–4}$

$mol$

$litre^{–1}$

$pOH = pH-14$
$pOH = –log_{10}[OH^–]$
$pOH = –log_{10}[H^+]$

$=–log_{10}×[10^{–4}]$

Then,

$=–(–4×log_{10}10)$

Since,

$pH=14 – pOH$

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