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Calculate the pH of 0.001 molar solution of HCl.
 
HCl is a  and is  in its solutions according to the
process:

HCl_{(aq)}→ H^+_{(aq)}+Cl^–{(aq)}
 
From this process, it is clear that one mole of HCl would give one mole of H^+ ions.
 
Therefore, the, i.e., 0.001 molar or 1.0\times10^{–3} mol litre^{–1}.
 
Thus, [H^+] = 1\times10^{–3} mol litre^{–1}

pH = –log_{10}[X]
 
Where, X is

= –log_{10}10^{–3}

Thus, pH=